Koshe Dekhi 8.2 Class 9 | Class 9 Koshe Dekhi 8.2 | গণিত প্রকাশ ক্লাস ৯ উৎপাদকে বিশ্লেষণ কষে দেখি ৮.২ সমাধান | WBBSE Class 9 Factorisation Koshe Dekhi 8.2 Solutions | WBBSE Class 9 Factorisation Chapter 8 Solution | উৎপাদকে বিশ্লেষণ কষে দেখি ৮.২ সমাধান | Ganit Prakash Class 9 Solution Koshe Dekhi 8.2 | Solution of WBBSE Class 9 Factoriasation Exercise 8.2 | গণিত প্রকাশ নবম শ্রেণি কষে দেখি ৮.২ সমাধান
Ganit Prakash Class 9 Koshe Dekhi 8.2 Solutions
নীচের বীজগাণিতিক সংখ্যামালাগুলিকে উৎপাদকে বিশ্লেষণ করি ।
WBBSE Class 9 Factorisation Koshe Dekhi 8.2 Ex 1 Solutions
WBBSE Class 9 Factorisation Koshe Dekhi 8.2 Ex 2 Solutions
গণিত প্রকাশ ক্লাস ৯ উৎপাদকে বিশ্লেষণ কষে দেখি ৮.২ Question ৩ সমাধান
Ex 3. 9p2–24pq +16q2+3ap–4aq
সমাধান:
9p2–24pq +16q2 +3ap–4aq
= (3p)2 – 2.3p.4q +(4q)2 + a(3p–4q)
= (3p–4q)2 + a(3p-4q) [যেহেতু, a2-2ab+b2= (a-b)2]
= (3p–4q)(3p–4q+a)
গণিত প্রকাশ ক্লাস ৯ উৎপাদকে বিশ্লেষণ কষে দেখি ৮.২ Question ৪ সমাধান
Ex 4. 4x4 +81
সমাধান:
4x4 +81
= (2x2)2 +92
= (2x2+9)2 – 2.2x2.9 [যেহেতু, a2+b2= (a+b)2 –2ab]
= (2x2+9)2 – 36x2
= (2x2+9)2 – (6x)2
= (2x2+9–6x) (2x2+9+6x) [যেহেতু, a2–b2= (a–b)(a+b)]
= (2x2–6x+9) (2x2+6x+9)
উৎপাদকে বিশ্লেষণ কষে দেখি ৮.২ Question ৫ সমাধান
Ex 5. x4-7x2+1
সমাধান:
x4–7x2+1
= x4 +2x2–9x2 +1
= [x4 +2x2+1]–9x2
= [(x2)2 +2x2 +1] –(3x)2
= (x2 +1)2 – (3x)2 [যেহেতু, a2+2ab+b2 = (a+b)2]
= (x2 +1–3x)(x2 +1+3x) [যেহেতু, a2–b2 = (a–b)(a+b)]
= (x2 –3x+1)(x2+3x+1)
WBBSE Class 9 Factoriasation Solution Of Exercise 8.2 Chapter 8, Question 6 Solution
Ex 6. p4–11p2q2+q4
সমাধান:
p4 –11p2q2+q4
=p4 –2p2q2 –9p2q2+q4
=[p4 –2p2q2 +q4]–9p2q2
=[(p2)2 –2p2q2 +(q2)2] –9p2q2
=(p2–q2)2 – (3pq)2 [যেহেতু, a2–2ab+b2 = (a–b)2]
=(p2–q2 –3pq) (p2–q2+3pq) [যেহেতু, a2–b2 = (a–b)(a+b)]
=(p2–3pq –q2) (p2 +3pq–q2)
Ganit Prakash Class 9 Koshe Dekhi 8.2 Ex 7 Solution
Ex 7. a2+b2–c2–2ab
সমাধান:
a2+b2–c2–2ab
= [a2–2ab+b2]–c2
= (a–b)2 –c2
= (a–b–c)(a–b+c) [যেহেতু a2–b2 = (a–b)(a+b)]
Ganit Prakash Class 9 Koshe Dekhi 8.2 Question 8 Solution
Ex 8. 3a(3a+2c)–4b(b+c)
সমাধান:
3a(3a+2c) –4b(b+c)
= 9a2+6ac –4b2–4bc
= [9a2–4b2] +6ac –4bc
= [(3a)2–(2b)2] + 2c(3a–2b)
= (3a–2b)(3a+2b) +2c(3a–2b) [যেহেতু, a2–b2 = (a–b)(a+b)]
= (3a–2b)(3a+2b+2c)
Gonit Prokash Class 9 Koshe Dekhi 8.2 Question 9 Solution
Ex 9. a2–6ab+12bc–4c2
সমাধান:
a2–6ab+12bc–4c2
=[a2–4c2] –6ab +12bc
=[a2–(2c)2] –6b(a–2c)
=(a–2c)(a+2c) –6b(a–2c) [যেহেতু, a2–b2 = (a–b)(a+b)]
=(a–2c) (a+2c–6b)
=(a–2c) (a–6b+2c)
Ganit Prakash Class 9 Koshe Dekhi 8.2 Ex 10 Solution
Ganit Prakash Class 9 Koshe Dekhi 8.2 Ex 11 Solution
Ganit Prakash Class 9 Koshe Dekhi 8.2 Ex 12 Solution
Ex 12. a2–9b2+4c2–25d2–4ac+30bd
সমাধান:
a2–9b2+4c2–25d2–4ac+30bd
= [a2–4ac +4c2] – [9b2–30bd +25d2]
= [a2–2.a.2c +(2c)2] – [(3b)2 – 2. 3a. 5d +(5d)2]
= (a–2c)2 – (3b–5d)2 [যেহেতু, a2–2ab+b2 = (a–b)2]
= [(a–2c)–(3b–5d)] [(a–2c)+(3b–5d)] [যেহেতু, a2–b2 = (a–b)(a+b)]
= (a–3b–2c+5d) (a+3b–2c–5d)
WBBSE Class 9 Factorisation Koshe Dekhi 8.2 Ex 13 Solution
Ganit Prakash Class 9 Koshe Dekhi 8.2 Ex 14 Solution
Ex 14. x2–2x– 22499
সমাধান:
x2–2x–22499
= x2–2x+1–22500
= x2–2.x.1+12 –22500
= (x–1)2 – (150)2 [যেহেতু , a2–2ab+b2 = (a–b)2]
= (x–1–150 )(x–1+150) [যেহেতু , a2–b2 = (a–b)(a+b)]
= (x–151)(x+149)
WBBSE Class 9 Math Koshe Dekhi 8.2 Ex 15 Solutions
