What is the Square Root of i [Polar Form]

Note that i=√-1 is an imaginary complex number. The square root of i is equal to ±(1+i)/√2. In this post, we will learn how to find the square root of i.

What is the Square Root of i

We have:

i=122i

= 12(1+2i1), adding 1 and subtracting 1 will change nothing.

= 12(1+2i+i2) as we know that i2=-1.

= 12(1+i)2 using the identity a2+2ab+b2=(a+b)2

So we have obtained that

i=12(1+i)2

Now, taking the square root on both sides will give us the square root of i. That is,

i=±12(1+i)

So the value of the square root of i, that is, the square root of iota is equal to ±(1+i)/√2. We write it as follows:

i=±12(1+i).

Square Root of i in Polar Form

We know that the polar form i is equal to

i=eπ/2

We take square root on both sides. Thus,

i=±eπ/4 as √x=±x1/2

i=±eπ/4

= ± [cos(π/4) + i sin(π/4)]

= ± [1/√2 + i/√2]

= ±(1+i)/√2.

Therefore, the value of square root of i is equal to ±(1+i)/√2 and this is obtained by using the polar form of a complex number.

ALSO READ:

How to multiply complex numbers

FAQs

Q1: What is square root of i?

Answer: The square root of i is ±(1+i)/√2.

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