The differentiation of e^tanx is equal to sec2x etanx. In this post, we will learn how to differentiate e to the power tanx with respect to x.
The following two formulas will be used to find the derivative of etanx.
- d/dx(tanx) = sec2x.
- loga ak =k.
Now, we will learn to find the derivative of e to the power tanx with respect to x.
How to Find the derivative of etanx
Question: How to differentiate etanx?
Solution:
Let y= etanx
Taking natural logarithms on both sides, we get that (natural logarithm means the logarithm with base e, i.e. loge)
log y = tanx (here we used the logarithm rule logeek =k.)
Now, differentiate both sides with respect to x. This will give us
$\dfrac{1}{y} \dfrac{dy}{dx}$ = sec2x as we know that the derivative of tanx is sec2x.
⇒ $\dfrac{dy}{dx}$ = y sec2x
Putting the value of y, that is, y=etanx, we get from above that
$\dfrac{d}{dx}$(etanx) = sec2x etanx.
Thus, the differentiation of etanx with respect to x is equal to etanx sec2x.
Video solution on derivative of etanx:
ALSO READ:
Derivative of arc(cotx): The derivative of arc(cotx) is -1/(1+x2).
Differentiate esinx: The derivative of esinx is esinx cosx.
Differentiate ecosx: The derivative of ecosx is -ecosx sinx.
FAQs
Q1: What is the derivative of etanx?
Answer: The derivative of e^tanx is equal to sec2x etanx.
Q2: If y=etanx, then find dy/dx?
Answer: If y=etanx, then dy/dx = sec2x etanx.